Ln T How Do I Use Integration By Parts To Find The Integral -2x Ln(x) Dx?

Sunday, January 3, 2010

How do I use integration by parts to find the integral -2x ln(x) dx? - ln t

I am always confused when working with ln.

δoτ said...: Well, not really, know that ∫ ln (x) dx = XLNX - x + C, so that it distinguished.

u = nx
du = (1 / x) dx
dv dx =- 2x
v =- x ²

² x-lnx - ∫ x ² - (1 / x) dx

LNX-x ² x dx + ∫

LNX-x ² + (1 / 2) x ² + C

(1 / 2) ² x (1 - 2lnx) + C; January 8, 2010 at 5:12 AM
CogitoEr... said...: Ask yourself how it seems like it would be easier. Differentiate ln (x) or integration?

The truth is that it does not really count. Either it works in both directions, or the usual way. Big deal. To develop through trial and error until you get a feel for them.

The very simple and clear, and I have no problem for you because you do not know where they first attempt; January 8, 2010 at 5:34 PM

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